To solve this problem, we must remember that there are 12 months in a year. To find the number of months in 3 years, we must multiply the number of months in a year (12) by the number of years (3).
12 * 3 = 36
Now, if we lease the car at $605 per month, we must multiply this number by the number of months leased (36) in order to find the total cost of the lease. Since this is an estimate, we can round 36 to 35 and $605 to $600 in order to make our computations easier.
$605 * 36 ≈ $600 * 35 = $21,000
Therefore, a good estimate for the lease is $21,000. If we want to check our work, we can always compute how much the lease would actually cost by solving $605 * 36 = $21,780. Because these two numbers are relatively close, we can infer that our estimate is reasonable.
Hope this helps!
With witch problem?
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Answer:
12 dozen
Step-by-step explanation:
create a proportion of: dozen cookies / cups of pecan
let 'd' = dozen cookies
(3/1 ÷ 5/4) = (d ÷ 5)
simplify 3/1 ÷ 5/4 to be: 3/1 x 4/5, which equals 12/5
12/5 = d/5
cross-multiply to get:
5d = 60
d = 12
Answer:
12
Step-by-step explanation:
1) 5+19−6(5+1−4)
2)5+19−6(6−4)
3)5+19−(6)(2)
4)5+19−12
5) 5+7
6) 12
Answer:
P = 100x + 75y
Step-by-step explanation:
The objective is profit, so the objective function is the function that defines profit:
P = 100x + 75y
where x is the number of large clocks made and y is the number of small clocks made per day.
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<em>Comment on other choices</em>
Inequalities are generally associated with constraints on the manufacturing. Here, those would be ...
- 0 ≤ x ≤ 5 no more than 5 large clocks
- 0 ≤ y ≤ 6 no more than 6 small clocks
- x + y ≤ 8 no more than 8 clocks total
The variables are constrained to be non-negative, because we cannot build a negative number of clocks.
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To maximize profit in this situation, the maximum possible number of large clocks should be produced, since they are the most profitable. Then the remaining capacity should be used to produce as many small clocks as possible: 5 large clocks and 3 small clocks for a profit of $725 per day.