1. remember all of them add up equal to 360 degree.
2. add all of them up together

3. combine like term then solve for Y
4. you will figure the arc measure of BC when you get answer for Y.
Answer:
8
Step-by-step explanation:
let the number=x
8(x-2)=16(x-5)
divide by 8
x-2=2(x-5)
x-2=2x-10
2x-x=-2+10
x=8
Answer:
A,C,D,E
Step-by-step explanation:
If you plug in any random number and you graph it for each one of the problems the answer will change
Answer:
The rate of change of the volume
when the height is 9 centimeters and the radius is 6 centimeters is 
Step-by-step explanation:
This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.
From the information given we know:


- The volume of a cone of radius r and height h is given by

We want to find the rate of change of the volume
when the height is 9 centimeters and the radius is 6 centimeters.
Applying implicit differentiation to the formula of the volume of a cone we get
![\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%5Br%5E2%5Cfrac%7Bdh%7D%7Bdt%7D%2B2rh%5Cfrac%7Bdr%7D%7Bdt%7D%20%5D)
Substituting the values we know into the above formula:
![\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%5B%286%29%5E2%5Cfrac%7B1%7D%7B2%7D%2B2%286%29%289%29%5Cfrac%7B1%7D%7B2%7D%20%5D%5C%5C%5C%5C%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%5B18%2B54%5D%5C%5C%5C%5C%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B72%5Cpi%7D%7B3%7D%3D24%5Cpi%20%5C%3A%5Cfrac%7Bcm%5E3%7D%7Bs%7D)
Answer:
The area of the warehouse B is 1150 square feet.
Step-by-step explanation:
Let
,
are the width and length of the warehouse A, in inches. The areas of the each warehouse are described below:
(1)
(2)
Where:
- Area of the warehouse A, in square inches.
- Area of the warehouse B, in square inches.
If we know that
, then by (1) and (2) we have the following equation:


The area of the warehouse B is 1150 square feet.