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Gekata [30.6K]
3 years ago
10

A ratio of two numbers is equal to 3:8. If the smaller number is 12,find the greater number.​

Mathematics
1 answer:
iragen [17]3 years ago
6 0

<em>The other no. is:</em>

<u><em>32</em></u>

<em>As you can see that in the ratio given, </em><em>3</em><em> is the smaller no. and </em><em>12</em><em> too.</em>

<em>So when we divide </em><em>12 </em><em>by </em><em>3</em><em>, we get </em><u><em>4 </em></u>

<em>Then to find the other no. we need to multiply </em><em>4</em><em> with </em><em>8</em><em> (which is the other no.          in the ratio given)</em>

<em>Therefore, we get the other no. as </em><u><em>32</em></u>

<em>And also when you divide </em><em>12</em><em> by </em><em>32</em><em>, </em>

<em>You get the answer as </em><u><em>3</em></u><u><em> by </em></u><u><em>8</em></u><em> </em><em>(which is the given ratio) </em>

<em />

<em>Hope you found this helpful!</em>

<em>THANK YOU!!</em>

<em>∝</em><em> Sidhdi</em>

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Step-by-step explanation:

let the number=x

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2 years ago
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Step-by-step explanation:

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the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant
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Answer:

The rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters is 24\pi \:\frac{cm^3}{s}

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

  • \frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • \frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}
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We want to find the rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]

Substituting the values we know into the above formula:

\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}

5 0
4 years ago
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Answer:

The area of the warehouse B is 1150 square feet.

Step-by-step explanation:

Let x, y are the width and length of the warehouse A, in inches. The areas of the each warehouse are described below:

A_{A} = x\cdot y (1)

A_{B} = \left(\frac{1}{2}\cdot x \right)\cdot \left(\frac{1}{3}\cdot y \right) (2)

Where:

A_{A} - Area of the warehouse A, in square inches.

A_{B} - Area of the warehouse B, in square inches.

If we know that A_{A} = 6900\,ft^{2}, then by (1) and (2) we have the following equation:

A_{B} = \frac{1}{6}\cdot A_{A}

A_{B} = 1150\,ft^{2}

The area of the warehouse B is 1150 square feet.

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