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ira [324]
3 years ago
13

What is the greatest common factor of 54,30,78?  pleaseeeeee help lol 

Mathematics
1 answer:
Contact [7]3 years ago
5 0
Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 54\ and\ 30\\and\ 78\ can\ be\ divided\\\\
54:2\\
27:3\\9:3\\3:3\\\\
30:2\\
15:3\\
5:5\\\\78:2\\39:3\\13:13
\\\\GCF=2*3=6\\\\Greatest\ common\ factor\ of\ 54\ and\ 30\ and\ 78\ is\ equal\ to\ 6.

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A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest
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\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
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then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
7 0
3 years ago
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