<img src="https://tex.z-dn.net/?f=25%20-%20%28%20%5Csqrt%7B16%7D%20%20-%201%29%20%5Ctimes%20%283%20-%209%29%20%7B%3F%7D%5E%7B2%7

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3 years ago

D%20" id="TexFormula1" title="25 - ( \sqrt{16} - 1) \times (3 - 9) {?}^{2} " alt="25 - ( \sqrt{16} - 1) \times (3 - 9) {?}^{2} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

beks73 [17]3 years ago

4 0

the answer is

$- 83$

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A survey by the state health department found that the average person ate 208 pounds of vegetables last year and 125 5/8 pounds

Trava [24]

I think you would divide

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3 years ago

How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)

joja [24]

So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so

$\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}
\\\\\\
\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}
\\\\\\
\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}$

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3 years ago

What is the range of the function f(x) = -|X - 4| + 5?

Law Incorporation [45]

Answer:

Range = (-∞, 5)

Step-by-step explanation:

This is the absolute value function with transformation.

The parent function is f(x) = |x|

This function has a "negative" in front, so it makes it reflect about x axis

The -4 after x makes horizontal translation of 4 units right

the +5 at the end makes the function translate 5 units UP