Question

Gina is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 12 inches by 14 1/4 inches. She needs another rectangle that is 10 1/2 inches by 10 1/4 inches. How many Total square inches of construction paper does Gina need for her project

Answer 1

Answer:

278.63 square inches

Step-by-step explanation:

Gina needs to cut two types of rectangles.

Dimensions of one rectangle is given as,

Width = 12 inches

Length = $14\frac{1}{4}$ = $\frac{57}{4}$ inches

So, the area of this rectangular paper will be

Area = width × length = $12\times \frac{57}{4}$ = 171 inches²

Dimensions of the other rectangular paper has been given as

Width = $10\frac{1}{4}$ = $\frac{41}{4}$ inches

Length = $10\frac{1}{2}$ = $\frac{21}{2}$ inches

So, the area of this rectangle will be

Area = width × length = $\frac{41}{4} \times \frac{21}{2}$ = 107.63 inches²

Thus the total area she need to cut = 171 + 107.63 = 278.63 square inches.

Answer 2

Answer:

Total area of construction paper = 278.63 square inches

Step-by-step explanation:

Given:

Dimension for First rectangle = $12\times 14\frac{1}{4}$

Dimension for another rectangle = $10\frac{1}{2}\times 10\frac{1}{4}$

Solution:

First we find the area of the first rectangle

$Area = length\times width$

$A_{1} = 12\times 14\frac{1}{4}$

$A_{1} = 12\times \frac{57}{4}$

$A_{1} = \frac{12\times 57}{4}$

$A_{1} = 3\times 57$

$A_{1} = 171\ square\ inches$

Similarly, we find the area of the another rectangle.

$Area = length\times width$

$A_{2}= 10\frac{1}{2}\times 10\frac{1}4}$

$A_{2}= \frac{21}{2}\times \frac{41}4}$

$A_{2}= \frac{21\times 41}{2\times 4}$

$A_{2}= \frac{861}{8}$

$A_{2} = 107.63\ square\ inches$

So, the total square inches of construction paper is given as:

$A = A_{1}+A_{2}$

Substitute $A_{1}\ and \ A_{2}\ value$

$A=171+107.63$

A = 278.63 square inches

Therefore, Gina needs 278.63 square inches of construction paper for her project.