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miv72 [106K]
3 years ago
12

Pls help I’ll give brainliest

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

c i think

Step-by-step explanation:

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A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs ​$70. A season ski pass costs ​$300. The
MatroZZZ [7]

The number of days when the season pass would be less expensive than the daily pass is 5 days.

<h3>How many days would the season pass be less expensive?</h3>

The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)

$70d + $20d = $90d

The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)

$300 + $20d

When the season pass becomes less expensive, the inequality equation is:

Daily pass > season pass

$90d > $300 + $20d

In order to determine the value of d, take the following steps:

Combine and add similar terms: $90d - $20d > $300

70d > $300

Divide both sides by 70 d > $300 / 70

d > 4.3 days

Approximately 5 days.

To learn more about how to calculate inequality, please check: brainly.com/question/13306871

#SPJ1

5 0
1 year ago
What is the solution to 2x-8&lt;12 ? <br> A. X&lt;2<br> B. X&lt;8 <br> C. X&lt;10<br> D. X&lt;40
Maurinko [17]
2x - 8 < 12
2x < 12 + 8
2x < 20
x < 20/2
x < 10
3 0
3 years ago
I need help with this ​
Jet001 [13]

Answer:

it would be C.

Step-by-step explanation:

Solve the equation for  x  by finding  a ,  b , and  c  of the quadratic then applying the quadratic formula.

6 0
3 years ago
If a quadrilateral does not have two pairs of opposite sides that are parallel, then it may be a _____.
vivado [14]
It may be a trapezium
8 0
3 years ago
I don't understand the substitution method?
liq [111]
It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.

In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x

2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y

now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5

now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0

and now we have solved the problem. x=0 and y=-5

6 0
3 years ago
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