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3 years ago

What is the equation of the line that passes through the point (8,4) and has a slope of 3/2

Mathematics

1 answer:

iren [92.7K]3 years ago

3 0

Answer: Y= 3/2x-8=

Step-by-step explanation:Y=4 M= 3/2. X=-8

Y=mx+b

4 = 3/2(8)+b

4= 24/2+b

4= 12+b

-12=-12

-8=b

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See attached picture.

Andrei [34K]

Answer:

Step-by-step explanation:

Since the triangle is a right triangle, we can use SOH CAH TOA to find ?. 10 is OPPOSITE to ? and 21 is HYPOTENUSE to ?, so we can use SIN to find ?.

SIN(?) = 10/21

? = ARCSIN(10/21)

? = 28.437

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1 year ago

Fr e e p o i n t s a n d b r a i n l i e s t

lana66690 [7]

Answer:

Hiii

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the least common multiple of both 9 and 12

Crank

LCM is found by finding the factors of both and making sure that both are inthere
9=3 times 3
12=2 times 2 times 3
common one is 3
so we have to have at least 2 threes and 2 twos
2 times 2 times 3 tiimes 3=36
answer is 36

3 0

3 years ago

Read 2 more answers

What is the answer for 3r+8=2r+12

Marina86 [1]

Answer:

r=4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can anyone help me with these questions plz

KonstantinChe [14]

Answers:

7: 20 miles

8: 28 miles

9: 1 error

10: Their speed is 50

11: 365 words in 5 mins

Step-by-step explanation:

#7 and #8

Our equation is: $f=2.25+0.20(m-1)$ With f meaning "fare" (price) and m meaning "miles".

Question 7 - Juan's fare for his ride costs $6.05. We must solve for $m$ .

Step 1. Substitute - Substitute the fare for $f$ in the equation.

$6.05=2.25+0.20(m-1)$

Step 2. Simplify/Solve - Solve for $m$ .

$6.05=2.25+0.20(m-1)$

- Distribute

$6.05=2.25+0.2m-0.2$

- Subtract 0.2 from 2.25

$6.05=2.05+0.2m$

- Subtract -2.05 from 6.05

$4=0.2m$

- Divide both sides by 0.2

$20=m$

And you have your answer of 20 miles.

Question 8 - Same equation, different fare.

Step 1. Substitute

$7.65=2.25+0.20(m-1)$

Step 2. Solve

$7.65=2.25+0.20(m-1)\\7.65=2.25+0.20m-0.20\\7.65=2.05+0.20m\\5.6=0.20m\\28=m$

And like so, we have $m = 28$

Questions 9 - 11

The equation given is $S=\frac{1}{5} (w-10e)$ . S = typing speed, w = words per 5 mins, and e= errors.

Question 9 -

We are given this information: S = 55, W = 285. We are solving for e.

Substitute -

$55=\frac{1}{5} (285 -10e)$

Solve -

$55=\frac{1}{5} (285 -10e)\\55=\frac{1}{5} (285 -10e)\\55= 57-2e\\-2=-2e\\1=e$

So they would make 1 error.

Question 10 -

Information given: 300 = w, 5=e. We are solving for S

Substitute -

$S= \frac{1}{5} (300-10(5))$

Solve -

$S= \frac{1}{5} (300-10(5))\\S= \frac{1}{5} (300-50)\\S= \frac{1}{5} (300-50)\\S= \frac{1}{5} (250)\\S= 50$

Their speed is 50.

Question 11 -

Information given: S = 65, e = 4. We are solving for w.

Substitute -

$65=\frac{1}{5} (w-10(4))$

Solve -

$65=\frac{1}{5} (w-10(4))\\65=\frac{1}{5} (w-40)\\65=\frac{1}{5}w-8\\73=\frac{1}{5}w\\365=w$

So w = 365.

Hoped this helped!~

7 0

3 years ago