ANSWER QUICK!!

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

(I NEED THIS ANSWERED SUPER SUPER FAST PLEASE IT'S IMPORTANT!!!!!!)<br><br> 6 7/8c =__ fl oz

Olegator [25]

1 cup = 8 fluid ounces.
6.875 cups = ? fluid ounces.
8*6.875=55.

Your answer would be 55 fluid ounces.

8 0

3 years ago

A researcher records the hospital admission rates for coronary heart disease at 10 local hospitals. She finds that 2 different h

In-s [12.5K]

The central tendency researcher use to describe these data is "mode".

The value that appears most frequently in a data set is called the mode. One mode, several modes, or none at all may be present in a set of data. The mean, or average of a set, and the median, or middle value in a set, are two more common measurements of central tendency.

Calculation of mode is done by-

The number that appears the most frequently in a piece of data is its mode.
Put the numbers in ascending order by least to greatest, then count the occurrences of each number to quickly determine the mode.
The most frequent number is the mode.
Simply counting how many times each number appears in the data set can help you identify the mode, which is the number that appears the most frequently in the data set.
The figure with the largest total is the mode.
Example: Since it happens most frequently, the mode for the data set [5, 7, 8, 2, 1, 5, 6, 7, 5] is 5.

To know more about the mode of the data, here

brainly.com/question/27951780

#SPJ4

6 0

1 year ago

What the simplest radical form of square root of 50 is

vekshin1

The answer to this is 5√2

3 0

3 years ago

How many ways can you make 35?

Ksju [112]