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4 years ago

Conducting financial transactions through the internet on your cell phone is known as

Mathematics

2 answers:

Pepsi [2]4 years ago

6 0

I think the answer is D

strojnjashka [21]4 years ago

3 0

Answer:I believe it is c

Step-by-step explanation: I'm not quite sure but I think it's c look another answer first before you pick mines

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The difference from home to

Amanda [17]

Answer:

$\frac{3}{8}\ mile$

Step-by-step explanation:

-Amy walks a distance of 7/8 mile

-Tom walks a distance of 4/8 mile.

#We immediately notice that Amy has walked a longer distance than Tom.

We subtract Tom's distance from Amy's to find how much further Amy walked;

$\bigtriangleup d=d_A-d_T\\\\=\frac{7}{8}-\frac{4}{8}\\\\=\frac{3}{8} mile$

Hence, Amy has walked 3/8 miles further than Tom has.

6 0

3 years ago

Please hurry this is timed and I only have 20 mins left!!!

Nadusha1986 [10]

Answer:

x = 6 2/3 The supplementary pair of angle is 78 degree and z = 112degree = 180 degree First step is where we can also see z its opposite angle is vertical opposite angle to 112 degree given and label as vertical angle - where we see a line through the 180 degree line at any angle we can call the pair supplementary- Pairs OR sets of angles an only be called consecutive when they are grouped with a set of parallel line across a straight line and it is only because they add up to 180 they could be either terms so as there isn't parallel shown ; we know we an call a pair of angles upon a straight line supplementary.angles.

Step-by-step explanation:

6 x +38 (+112) = 180 degree as angles on a straight line add up to 180 6 x +38 (+112) = 180 6 x +140 = 180 6 x + 140- 140 = 180-140 6 x = 40 x = 40/6 x = 6.66666667 x = 6 2/3 Proof (6( 6 2/3)) + 38 + 112 = 180 = (40+38)+112 = 180 = 78 +112 = 180 Proves the supplementary angle is 78 degree.

5 0

3 years ago

50 points, brainIiest, 5 stars, and a thanks. please help me :(

Ulleksa [173]

Answer:

Step-by-step explanation:

Hope it helps!

4 0

3 years ago

Read 2 more answers

Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S

Sophie [7]

Answer:

Recall that a relation is an equivalence relation if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

Reflexive: We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that $A=J^{-1}AJ$ . Thus, A↔A.

Symmetric: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that $A=P^{-1}BP$ . In this equality we can perform a right multiplication by $P^{-1}$ and obtain $AP^{-1} =P^{-1}B$ . Then, in the obtained equality we perform a left multiplication by P and get $PAP^{-1} =B$ . If we write $Q=P^{-1}$ and $Q^{-1} = P$ we have $B = Q^{-1}AQ$ . Thus, B↔A.

Transitive: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have $A=P^{-1}BP$ and from B↔C we have $B=Q^{-1}CQ$ . Now, if we substitute the last equality into the first one we get