Which is a benefit of the space shuttle?

2 answers:

7 0

The benefit of the space shuttle is that A. it's reusable. This means that after this shuttle has been used for one mission, it can be use for numerous other missions again, until it gets broken and cannot run anymore. B is incorrect because it cannot land - it is only there to observe. C is incorrect because more than one person can fit. D is incorrect because it doesn't orbit the Earth permanently - it returns at one point.

GREYUIT [131]3 years ago

7 0

I think its a because i did this test a long time a go on k12

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What is the mass of 531 ml of a liquid that has a density of 0.760 g/ml?

pogonyaev

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404g if 3 sig figs

4 0

3 years ago

Indicate whether the following are acidic, basic, or neutral solution

goldenfox [79]

You answer this by using the pH formula and and the relation of pH and pOH, pH = -log[H+] and 14 = pH + pOH. The correct classification are as follows:

A. [H2O+]=6.0x10^-12
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B. [H3O+]=1.4x10^-9
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C. [OH-]=5.0x10^-12
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D. {OH-]=3.5x10^-10
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Hope this answers the question.

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3 years ago

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katen-ka-za [31]

Answer:

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Explanation:

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2 years ago

In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,

Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

$\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}$

$\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}$

$Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz$

Therefore, the signal is at 11759 Hz from the TMS.

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3 years ago