This is an incomplete question, here is a complete question.
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.
Answer : The specific heat of a material is, 0.137 J/g.K
Explanation :
Formula used to calculate the specific heat of a material is:
where,
q = heat absorbed = 96 J
m = mass of sample = 35 g
c = specific heat capacity of material = ?
= initial temperature = 293 K
= final temperature = 313 K
Now put all the given values in the above formula, we get:
Therefore, the specific heat of a material is, 0.137 J/g.K
Answer: The friction force.
Justification:
Since the box is sliding over the table, the normal force equals the weight of the object (and any other vertical force that is applied on the box).
So, the normal force and weight (along with any other vertical component of a force applied on the box) must be 10 N and 10 N.
The other two forces: 14 N and 7 N are the forces in the plane of the table and should be opposite in a same line. The 14 N force is the responsible of the motion and the 7N force is opposing the 14 N force, so the 7N force has to be the friction force. Of course, 14N - 7N > 0 which is why the box is moving.
A conversion factor is a fraction that is always equal to the value of 1.
5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.
where,
- <em>c: specific heat capacity of gold</em> (0.129 J/g.°C)
- ΔT: change in the temperature
5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
You can learn more about heating here: brainly.com/question/1105305
Answer:
Q = 2.60 • 
J
Explanation:
Our specific heat capacity equation is:
Q = mC∆T
Q is the energy in joules.
m is the mass of the substance.
∆T is the temperature chance.
Let's plug in what we know.
- We have 76.0 g of octane
- The specific heat capacity of octane is 2.22 J/(g•K)
- The temperature increases from 10.6º to 26.0º (a 15.4º increase)
Q = 76.0(2.22)(15.4)
Multiply.
Q = 2598.288
We want three significant figures.
Q = 2.60 •
or
Q = 2590 J
Hope this helps!
