Hello,
1 answer:
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Let
x--------> the larger integer
y-------> the smaller integer
we know that
x²+y²=394-----> equation 1
x=y+2-----> equation 2
substitute equation 2 in equation 1
[y+2]²+y²=394-----> y²+4y+4+y²=394
2y²+4y-390=0
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
y=13
x=y+2---> x=13+2---> x=15
the answer is
the numbers are 15 and 13
x--------> the larger integer
y-------> the smaller integer
we know that
x²+y²=394-----> equation 1
x=y+2-----> equation 2
substitute equation 2 in equation 1
[y+2]²+y²=394-----> y²+4y+4+y²=394
2y²+4y-390=0
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
y=13
x=y+2---> x=13+2---> x=15
the answer is
the numbers are 15 and 13