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Paraphin [41]
3 years ago
13

The immune system is a network of cells . Tissue,and organs that help ______?

Biology
1 answer:
Dima020 [189]3 years ago
3 0
<span>The immune system is a network of cells . Tissue,and organs that help defend the body.

Hope I helped! Have a great one!


</span>
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Inflammation
lesya692 [45]

Answer: option D - is initiated by the buildup of dead cells and bacteria

Explanation:

Inflammation is a medical condition that affect a part of the body, consisting of congestion of the blood vessels, with obstruction of the blood current, and growth of morbid tissue. It is manifested outwardly by redness and swelling, attended with heat and pain.

Note that the CONGESTION and OBSTRUCTION of blood vessels is INITIATED by buildup of dead cells and bacteria.

6 0
3 years ago
How do we classify finger prints?
Aloiza [94]
Classifying Fingerprints. Once the fingerprints are taken and labeled, forensic scientists use a classification system to identify them. The three basic fingerprint patterns are Whorl, Arch, and Loop. There are more complex classification systems that further break down the pattern to plain arches or tented arches. Hope this helps
6 0
3 years ago
Assuming that the average protein in E. coli consists of a chain of 380 amino acids, calculate the maximum number of proteins th
Afina-wow [57]

Answer:

4210.5 proteins

Explanation:

(a)The amount of nucleotide pairs in the DNA molecule calculated using

=molecular weight of DNA/molecular weight of a single pair

molecular weight of DNA

= 3.1 × 10^9g/mol

molecular weight of a single pair

= 0.66 ×10^3g/mol

= (3.1 × 10^9g/mol)/(0.66 × 10^3g/mol)

= 4.7 10^6pairs

Lets, Multiply the number of pairs with the length per pair

Take, length per pair = 0.34 nm/pair

= (4.7 × 10^6pairs)(0.34 nm/pair)

= 1.6 × 10^6nm

= 1.6 mm

= (approx 2mm or 0.002 mm).

Therefore,

the DNA is

(1.6 mm)/(0.002 mm)

= 800

The DNA is 800 times times longer than the cell.

This indivates Tat DNA must be tightly coiled to fit into the cell.

(b) the amount of DNA molecule nucleotide pairs has given

= 4.7 × 10^6 nucleotide pairs,

From solution (a), there must be one-third this number of triplet codons

= (4.7 × 10^6)/3

= 1.6 × 10^6codons

If an individual protein has an average of 380 amino acids, each needs a codon,

the number of proteins that can be coded by E. coli DNA

= (1.6 × 10^6codons) × (1 amino acid/codon)

---------------------------------------------

(380 amino acids/protein)

= 4210.5 proteins

________________________

Here is the complete question

The genetic information contained in DNA consists of a linear sequence of coding units known as codons. Each codon consists of three adjacent DNA nucleotides that corresponto a single amino acid in a protien.

The E.coli DNA molecule contains 4.70 x 10^6 base pairs. Determine the number of codons that can be present.

Assuming that the average protein in E.coli consists of a chain of 400 amino acids, calculate the maximum number of protiens that can be coded by an E.coli DNA molecule

7 0
3 years ago
___ invented the ____
Andrews [41]
C. and the explanation is i just know
3 0
2 years ago
Read 2 more answers
What are the two active sites or domains on a repressor protein?
n200080 [17]

Answer:

DNA binding domain and allosteric domain

Explanation:

Repressors are proteins that inhibit gene expression, They usually have DNA or RNA binding site which enables them to binde to the operator or associated silencers. Allosteric domain is the site for the binding of other molecules, such as  corepressors and inducers that regulate repressor's activity.

3 0
3 years ago
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