Answer:
The ratio of salmon to total fish caught is 9 over 25.
Step-by-step explanation:
Start with what we know. We have 200 total fish caught and 36% are salmon. The rest is just mumble jumble so don't pay attention to that.
All we have to do is find 36% of 200, and the easiest way to do that is by first knowing that 36% of 100 is 36 so if we double that it will give us 36% of 200.
36 x 2 = 72
So, the ratio of salmon to total fish caught is 72 over 200. But, in simplest form is 9 over 25 because 72/200 divided by 4/4 = 9/25.
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Where’s the data?................
9514 1404 393
Answer:
(a) cos(55°) = 11/x
Step-by-step explanation:
The marked sides are the hypotenuse (x) and the side adjacent to the given angle (11). Then the relevant trig ratio is ...
Cos = Adjacent/Hypotenuse
cos(55°) = 11/x
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y. the dimensions you want are therefore x and y.
The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y. We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.
The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128. Let's reduce this by dividing all three terms by 4: 2x + y = 32.
Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32. The formula for area is A = L * W. Solving 2x + y = 32 for y, we get y = -2x + 32.
We can now eliminate y. The area of the patch is (x)(-2x+32) = A. We want to maximize A.
If you're in algebra, find the x-coordinate of the vertex of this quadratic equation. Remember the formula x = -b/(2a)? Once you have calculated this x, subst. your value into the formula for y: y= -2x + 32.
Now multiply together your x and y values to obtain the max area of the patch.
If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero. This approach should give you the same x value as before; the corresponding y value will be the same; y=-2x+32.
Multiply x and y together. That'll give you the maximum possible area of the garden patch.
