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Vesna [10]
3 years ago
5

If a picnic area is located at the midpoint between Sacramento and Oakland, find the distance to the picnic area from the road s

ign.
Roseville 5
Sacramento 23
Oakland 110
Mathematics
1 answer:
Oxana [17]3 years ago
7 0
First, think this through. If you are 23 miles from Sacramento, and 110 miles from Oakland (I am assuming it is miles since you didn't specify *cough cough*) then the two cities are 133 miles apart (also assuming you are in between them)
23miles + 110miles = 133miles
so, we use the midpoint formula to find our position
\frac{distance}{ 2}
and get 66.5 miles from both Sacramento and Oakland.

Next, we already know the sign is 23 miles away from Sacramento so we can use that distance and our position to figure out how far away the sign is. We use absolute values because distance is always positive.
|our \: position - distance \: of \: sign|

so we get
|66.5miles - 23miles|  = 43.5miles
to double check, use the sign's distance from Oakland.
|66.5miles - 110miles|  = 43.5miles
so, we are 43.5 miles from the sign!

hope this helps

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At Sally's Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the res
Marina86 [1]

Answer:

Probability that their hair was done by Amy is 0.475.

Step-by-step explanation:

We are given that Sally's Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the rest are done by Amy.

Let the Probability of hair cutting done by Chris = P(C) = 0.36

Probability of hair cutting done by Karine = P(K) = 0.26

Probability of hair cutting done by Amy = P(A) = 0.368

Also, let NS = event that customer is not satisfied with his cutting

So, Probability that customers are not satisfied given that their hair cutting is done by Chris = P(NS/C) = 0.05

Probability that customers are not satisfied given that their hair cutting is done by Karine = P(NS/K) = 0.06

Probability that customers are not satisfied given that their hair cutting is done by Amy = P(NS/A) = 0.08

Now, a customer leaving the salon is selected at random. If the customer is not satisfied, the probability that their hair was done by Amy is given by = P(A/NS)

For finding the above probability we will use the concept of Bayes' Theorem;

SO, P(A/NS)  =  \frac{\text{P(A) \times P(NS/A)}}{\text{P(C) \times P(NS/C) + P(K) \times P(NS/K) +P(A) \times P(NS/A) }}\frac{P(A) \times P(NS/A) }{P(C) \times P(NS/C) +P(K) \times P(NS/K) +P(A) \times P(NS/A) }

                     =  \frac{0.38 \times 0.08}{0.36 \times 0.05+0.26 \times 0.06+0.38 \times 0.08}

                     =  \frac{0.0304}{0.064}

                     =  <u>0.475</u>

<em>Hence, the probability that their hair was done by Amy is 0.475.</em>

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3 years ago
A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki
shepuryov [24]

Answer

given,

mean = 12 Kg

standard deviation = 0.5 Kg

assume the observed statistic is = 11.1

 now, \bar{X}=11.1 , \mu = 12 , \sigma = 0.5

assuming the number of sample = 4

n = 4

Hypothesis test:

H₀ : μ≥ 12

Ha : μ < 12

now,

significant level α = 0.05

z* = \dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z* = \dfrac{11.1-12}{\dfrac{0.5}{\sqrt{4}}}

     z* = -3.60

Test statistics, Z* = -3.60

P-value

P(Z<-3.60) = 0.002 (from z- table)

P- value = 0.002

now,

reject the value of H₀ when P-value < α

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since, it is less P-value < α , we have to reject the null hypothesis

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Ket [755]

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slega [8]

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Time must be in years to find the rate per annum.

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Divide the time by 12.

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Now, find the rate of interest using simple interest formula.

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$26.25\times 100 =500\times r\times \frac{3}{2}

$2625 =250\times r\times 3

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⇒ r = 3.5%

Hence the annual interest rate is 3.5%.

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