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Stolb23 [73]
3 years ago
10

Please help me i dont get it

Mathematics
2 answers:
dolphi86 [110]3 years ago
7 0
Since y^2 + 6y + 9 can be factored, the polynomial is not factored all the way. To factor it, try (y + 3)(y+3) or simply put, (y +3)^2. Don't forget to keep the 6y^2, so the completely factored version would be : 6y^2 (y+3)(y+3)
Nesterboy [21]3 years ago
4 0
I can see your problem immediately . . . there's no question !
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Which value of b would make x²+bx-30 factorable?<br> A. -31<br> B. -17<br> C. 11<br> D. 13
dimulka [17.4K]

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b±\sqrt{b^{2}-4ac} /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since \sqrt{13^{2}-4*1*(-30) = \sqrt{289} = 17. So b=13.

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4 years ago
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What is a coefficient
Bumek [7]

Answer:

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Step-by-step explanation:

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4 years ago
Naomi has earned $54 mowing lawns
Vinil7 [7]

Answer:

9$ per hour

Step-by-step explanation:

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Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the
Julli [10]

Answer:

a) z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53  

b) p_v =2*P(z

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

\bar X_{1}= 104 represent the mean for 1

\bar X_{2}= 106 represent the mean for 2

\sigma_{1}= 8.4 represent the population standard deviation for 1

\sigma_{2}= 7.6 represent the population standard deviation for 2

n_{1}=80 sample size for the group 1

n_{2}=70 sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

The statistic would be given by:

z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=(1)

Part a

Replacing we got:

z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53

Part b

The p value would be given by this probability:

p_v =2*P(z

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

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torisob [31]
The slope of line d is 1/4.
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