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Answer:
Kindly check explanation
Step-by-step explanation:
Using technology on the data above, the least square regression equation obtained is ;
y = 33.4528+2.7975x
Where, slope = 2.7975 ; Intercept = 33.4528
x = chirps per second, independent variable
y = temperature, predicted variable.
The Correlation Coefficient, r = 0.71
The Coefficient of determination, r² = 0.71² = 0.5041
The percentage of variation in y due to regression is the r² value, which is about 50.41%
Hence, the percentage variation in temperature due to the regression line is 50.4, while the rest is due to other factors.
Predicted temperature, y when x = 19 ;
Put x = 19
y = 33.4528+2.7975(19)
y = 86.60°
