Answer:
I think it is 1 because that is all that works for me
Not sure what quizScore1-5 is, but here it is. Also, I'm not entirely sure what language you're working with here, but null can't be returned as an integer. If it were a string, for example, it'd be possible as string is an object reference type.
public int getData(int dataNumber)
{
if (dataNumber == 1)
return quizScore1;
else if (dataNumber == 2)
return quizScore2;
else if (dataNumber == 3)
return quizScore3;
else if (dataNumber == 4)
return quizScore4;
else if (dataNumber == 5)
return quizScore5;
else
return 0;
}
Members of an Agile development team often agrees on what tasks to work on and they do it together. The one possible solution to this challenge is to Have the database developer train the rest of the team so there are fewer handoffs.
Agile development team often works together as a team. They as team discuss the task yo take, when it will take place etc.
This team is all about communication, teamwork, problem-solving etc.
Conclusively, A task should be completed by one member on the team, but the team may choose to pair up when doing the work.
Learn more from
brainly.com/question/24383225
See full question below:
Your agile team only has one person who knows how to develop database software. So the other developers finish their tasks and then wait for their work to be Integrated into the database. This creates a pile of backed up work for the database developer. But it also means that the other developers must either wait or add to the growing pile of database work. What's one possible solution to this challenge?
Select an answer:
Have the database developer train the rest of the team so there are fewer handoffs.
Have the software developers split their time between other teams so they're not as productive
Encourage the database developer to work overtime to catch up with their work.
Create a large batch of work so the database developer can focus on finishing
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.
Answer:
if(y==10)
{
x=0; // assigning 0 to x if y equals 10.
}
else
{
x=1; // assigning 1 to x otherwise.
}
Explanation:
In the if statement i have used equal operator == which returns true if value to it's right is equal to value to it's left otherwise false.By using this operator checking value of y and if it is 10 assigning 0 to x and if it is false assigning 1 to x.
