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Kaylis [27]
4 years ago
10

Graph the given relation or equation and find the domain and range. Then determine whether the relation or equation is a functio

n. (3.3, 5.3), (–1.7, 5.3), (–4.7, 3.3), (–4.7, –2.7)

Mathematics
1 answer:
KiRa [710]4 years ago
5 0

Domain: \{3.3,-1.7,-4.7\}

Range: \{5.3,3.3,-2.7\}

The relation is not a function.

Explanation:

The coordinates (3.3,5.3), (-1.7,5.3), (-4.7,3.3), (-4.7,-2.7) are plotted in the graph. The image of the graph is attached below.

The domain of a relation is the set of all x-values for which the function is well defined. Thus, the domain are \{3.3,-1.7,-4.7\}

The range of a relation is the set of all y-values obtained by substituting the values for x in the function. Thus, the range are \{5.3,3.3,-2.7\}

The relation (3.3,5.3), (-1.7,5.3), (-4.7,3.3), (-4.7,-2.7) is not a function since, -4.7 has two different y-values. By definition of function, the function cannot have two different y-values for the same x-value.

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ahrayia [7]

Answer:

k < - 1

Step-by-step explanation:

28 + 3k < 5(-3-8k)

28 + 3k < - 15 - 40k

28 + 15 < - 40k - 3k

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43/- 43 > k (switch signs because 43 is negative)

k < -1

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3 years ago
A sample size of n = 64 is drawn from a population whose standard deviation is o = 5.6.
AlekseyPX

Answer:

The margin of error for a 99% confidence interval for the population mean is 1.8025.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

\sigma = 5.6

So

M = 2.575*\frac{5.6}{\sqrt{64}} = 1.8025

The margin of error for a 99% confidence interval for the population mean is 1.8025.

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4 years ago
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Graphs attached

Done!

Hopw it helps

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