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2 years ago

Help please asap! Struggling with math graph problem

Mathematics

1 answer:

Kay [80]2 years ago

7 0

We're told (5,-2) is on the line, that's x=5, y=-2

First one y-5 = -7, (x+2)/3=7/3, not equal

Second one y+5=3, (x-2)/3=1, not equal

Third one y+2=0, (x-5)/3=0, TRUE, equal

Fourth one, y-2=-4 (5+5)/3=10/3, not equal

Answer: third choice y+2 = (1/3)(x+5)

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Please Help! Show all the steps!

likoan [24]

You can start by subtracting different equations from each other.

3x + 2y + 3z = 1

subtract

3x + 2y + z = 7

2z = -6

divide by 2

z = -3

add the following two expressions together:

3x + 2y + z = 7

3x + 2y + 3z =1

6x + 4y + 4z = 8

subtract the following two expressions:

6x + 4y + 4z = 8

5x + 5y + 4z = 3

x - y = 5

^multiply the whole equation above by 3

3x - 3y = 15

subtract the following two expressions:

3x - 3y = 15

3x + 2y = 10

-5y = 5

divide each side by -5

y=-1

take the following expression from earlier:

x - y = 5

substitute y value into above equation

x - - 1 = 5

2 negatives make a positive

x + 1 = 5

subtract 1 from each side

x = 4

Therefore x = 4, y = -1, z = -3

I checked these with all 3 equations and they worked :)

(it's quite complicated, comment if you don't understand anything) :)

7 0

3 years ago

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

6 0

3 years ago

7x ^4 minus 5x ^4 =

lapo4ka [179]

Answer:

2x^{4}

Step-by-step explanation:

You would subtract 7 and 5 and you would leave the exponent so it would be 2x^{4}

8 0

2 years ago

Read 2 more answers

Find the slope (-2,-4) (2,4)

Alex

Answer:

8 over 4

Step-by-step explanation:

5 0

3 years ago

How can numbers be expressed, ordered and compared?

USPshnik [31]

Numbers can be expressed, ordered and compared by a lot of mathematical principles, properties, models and paradigms. There are different properties of numbers to associate, group and distribute numbers. For example commutative property of addition, 1 + 2 = 3 can be 3 = 1 + 2. Moreover, numbers can be expressed by mathematical form, thus 100 wherein 1 is in the place order of hundreds. And so on… other examples can be mathematical symbols or inequality to compare numbers. For example, 1 > 2. One is less than 2.

6 0

3 years ago