Answer:
3x + 4 = 12
Step-by-step explanation:
plus = +
equal = =
but if you were looking for the answer to the equation
3x + 4 = 12
3x = 12 - 4 (the symbol changes bc i switched it to the other side)
3x = 8
x = 8/3
~batmans wife dun dun dun.....
In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.
In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
Y=17(1.2) you quantity is 20 so you move 2 decimals places over
Answer:
C. Different sample proportions would result each time, but for either sample size, they would be centered (have their mean) at the true population proportion.
Step-by-step explanation:
From the given information;
A political polling agency wants to take a random sample of registered voters and ask whether or not they will vote for a certain candidate.
A random sample is usually an outcome of any experiment that cannot be predicted before the result.
SO;
One plan is to select 400 voters, another plan is to select 1,600 voters
If the study were conducted repeatedly (selecting different samples of people each time);
Different sample proportions would result each time, but for either sample size, they would be centered (have their mean) at the true population proportion. This is because a sample proportion deals with random experiments that cannot be predicted in advance and they are quite known to be centered about the population proportion.
Answer:
P
(
sum
>
3
and
divisor of
24
)
=
7
18
Explanation:
Possible target sums that meet the given requirements:
XXX
{
4
,
6
,
8
,
12
}
Consider the possible die rolls that can give these sums:
sum
−−−−
xxx
first roll
−−−−−−−
second roll
−−−−−−−−−
4
1
3
2
2
3
1
6
1
5
2
4
3
3
4
2
5
1
8
2
6
3
5
4
4
5
3
6
2
12
−−
6
−
6
−
Giving a total of
14
out of a possible
36
combinations that meet the given requirements.
Step-by-step explanation:
