All categories

3 years ago

Write an equation in slope-intercept form, that contains the point (3,-2) and has a slope of -2

Mathematics

1 answer:

Mandarinka [93]3 years ago

3 0

Y=-2x+b
-2=-2(3)+b
-2= -6+b
b=4

The answer is y=-2x+4

You might be interested in

What is the mixed number form<br> of 33/8

goblinko [34]

HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

33-32=1 which is the numerator

Answer is :

4 1/8

4 0

3 years ago

Read 2 more answers

The game commission observes the fish population in a stream and notices that the number of trout increases by a factor of 1.5 e

just olya [345]

Answer:

A - $f(t)=80(1.5)^t$

B - Graph given below

C - Number of trouts in 5th week are 607.2

D - Population of trouts will exceed 500 on the 5th week.

Step-by-step explanation:

We are given that,

The number of trout increases by a factor of 1.5 each week and the initial population of the trout is observed to be 80.

Part A: So, the explicit formula representing the situation is,

$f(t)=80(1.5)^t$ , where f(t) represents the population of trouts after 't' weeks.

Part B: The graph of the function can be seen below.

It can be seen that the function is an exponential function.

Part C: It is required to find the number of trouts in the 5th week.

So, we have,

$f(5)=80(1.5)^5$

i.e. $f(5)=80\times 7.59$

i.e. f(5) = 607.2

Thus, the number of trouts in 5th week are 607.2

Part D: We are given that the trout population exceeds 500.

It is required to find the week in which this happens.

So, we have,

$50$

i.e. $(1.5)^t>\frac{500}{80}$

i.e. $(1.5)^t>6.25$

i.e. $t\log 1.5>\log 6.25$

i.e. $t\times 0.1761>0.7959$

i.e. $t>\frac{0.7959}{0.1761}$

i.e. t > 4.5

As, t represents the number of weeks. So, to nearest whole, t = 5.

Thus, the population of trouts will exceed 500 on the 5th week.

7 0

3 years ago

Quadratic Function PLEASE HELP!! questions attached below

marysya [2.9K]

28) ANSWER: x=5
Because 5*5=25.
29) ANSWER: x=4
3x^2=48
Divide both sides by 3.
x^2=16
x=4
Because 4*4=16.

4 0

3 years ago

Read 2 more answers

The scale of a map is 1:4 000 000. Hint: 1:4 000 000 means that 1cm on the map = 4 000 000 on the ground. The distance between L

GrogVix [38]

Answer:

325 km

Step-by-step explanation:

Given the scale :

1 : 4 ,000, 000

1cm measure in map = 4000000 on the ground

From the map :

Distance between Leeds and London = 8.125 cm

The actual distance on ground can be calculated thus :

1cm = 4,000,000

8.125cm = x

Cross multiply

x = 32500000 cm

Converting to kilometers :

1 km = 100,000 cm

x = 32500000

Cross multiply

100,000x = 32500000

x = 32500000 / 100000

x = 325

Hence, actual distance between Leeds and London is 325 km

3 0

3 years ago

The output with the y being -4

aivan3 [116]

For this case we have a function of the form $y = f (x)$ , where $f (x) = - 4x$ . We must find the values of "and" according to the following function: $y = -4x$

So:

$f (-6) = - 4 (-6) = 24\\f (-2) = - 4 (-2) = 8\\f (3) = - 4 (3) = - 12$

Thus, the values are:

24,8, -12

Answer:

24,8, -12

3 0

4 years ago