3 years ago

What are some specific organisms that help speed up the decay of biomes? Give me 2 answer

1 answer:

4 0

When it comes to organisms that help speed up the decay of biomes, worms are wonderful creatures. They take almost anything that falls to the earth and slowly erode it. Fungi is another option.

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A car is moving in a straight line with the same speed of 100 m/s ,the acceleration in this

Amiraneli [1.4K]

Answer:

a = 0m/s²

Explanation:

Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

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3 years ago

A student shakes a rope such that 20 complete vibrations are made in 4.00 seconds. Determine the vibrational frequency of the ro

fgiga [73]

Answer:

The vibrational frequency of the rope is 5 Hz.

Explanation:

Given;

number of complete oscillation of the rope, n = 20

time taken to make the oscillations, t = 4.00 s

The vibrational frequency of the rope is calculated as follows;

$Frequency = \frac{number \ of \ complete \ vibrations}{time \ taken} \\\\Frequency = \frac{20 }{4 \ s} \\\\Frequency = 5 \ Hz$

Therefore, the vibrational frequency of the rope is 5 Hz.

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3 years ago

ਭਾਰਤ ਵਿੱਚ ਸਭ ਤੋਂ ਵੱਧ ਵਰਖਾ ਕਿੱਥੇ<br>ਹੁੰਦੀ ਹੈ।

astra-53 [7]

Answer:

I don’t understand:(

3 0

3 years ago

A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?

katrin2010 [14]

Answer:

Just use F =ma where m is mass and a is acc.

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3 years ago

On a frictionless horizontal air table, puck A (with mass 0.252 kg ) is moving toward puck B (with mass 0.374 kg ), which is ini

geniusboy [140]

As we know that kinetic energy is given as

$KE = \frac{1}{2}mv^2$

Here we can find the initial speed of puck A by momentum conservation

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

$0.252\times v + 0 = 0.252\times (-0.115) + 0.374\times ( 0.650)$

$v = 0.850 m/s$

now here we will have initial kinetic energy of the mass is given as

$KE_i = \frac{1}{2}m_1v_1^2$

$KE_i = \frac{1}{2}(0.252)(0.850^2) = 0.091 J$

$KE_f = \frac{1}{2}(0.252)(-0.115)^2 + \frac{1}{2}(0.374)(0.650^2)$

$KE_f = 0.081 J$

now loss of energy is given as

$KE_i - KE_f = 0.091 - 0.081 = 0.010 J$

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3 years ago