Answer:
VB − VA = g tAB & (VA + VB)/2 = h / tAB
Explanation:
s = h = Displacement
tAB = t = Time taken
VA = u = Initial velocity
VB = v = Final velocity
a = g = Acceleration due to gravity = 9.8 m/s²
Hence, the equations VB − VA = g tAB & (VA + VB)/2 = h / tAB will be used
Answer:
T=+1.133N
Explanation:
Tension and weight are forces that have opposite directions
Weight is negative (downward)
W=m*g= 0.11kg*(-9.8m/s^2)
W= -1.078N
Tension is possitive (upward)
The total force will be the sum of both (the difference taking in consideration the direction)
Ft= T+W
Also the total force is the product of the mass due to acceleration:
Ft=m*a
Ft= +0.11kg*0.5m/s^2
Ft=+0.055N (upward)
Tension will be the difference between Ft and W:
T= Ft-W
T=+0.055N-(-1.078N)
T=+1.133N
Answer:
a) True. The number of photoelectrons is proportional to the amount (intensity) of the incident beam. From the expression above we see that threshold frequency cannot emit electrons.
b) λ = c / f
Therefore, as the wavelength increases, the frequency decreases and therefore the energy of the photoelectrons emitted,
c) threshold energy
h f =Ф
Explanation:
It's photoelectric effect was fully explained by Einstein by the expression
Knox = h f - fi
Where K is the kinetic energy of the photoelectrons, f the frequency of the incident radiation and fi the work function of the metal
a) True. The number of photoelectrons is proportional to the amount (intensity) of the incident beam. From the expression above we see that threshold frequency cannot emit electrons.
b) wavelength is related to frequency
λ = c / f
Therefore, as the wavelength increases, the frequency decreases and therefore the energy of the photoelectrons emitted, so there is a wavelength from which electrons cannot be removed from the metal.
c) As the work increases, more frequency radiation is needed to remove the electrons, because there is a threshold energy
h f =Ф
Answer:
Resistance, 
Explanation:
Given that,
Voltage of the battery, V = 9 volts
Current produced in the circuit, I = 17 A
We need to find the resistance when shorted by a wire of negligible resistance. It is a case of Ohm's law. The voltage is given by :
So, the resistance in the circuit is 0.529 ohms. Hence, this is the required solution.
