Calculate the initial speed of a box which slides on a horizontal floor surface and comes to rest after sliding 2 s. The coeffic
1 answer:
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Answer:
9 meters
Explanation:
Given:
Mass of Avi is,
Spring constant is,
Compression in the spring is,
Let the maximum height reached be 'h' m.
Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.
So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.
Decrease in elastic potential energy is given as:
Now, increase in gravitational potential energy is given as:
Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,
Therefore, Avi will reach a maximum height of 9 meters.
As we know that total work done by a force is given by
so it is product of force and displacement along same direction
as we can write it as
so it must be the product of force and displacement in same directions so correct answer must be
<u>B. in the same direction as the displacement vector and the motion.</u>
Answer:
Explanation:
Given that:
the initial angular velocity
angular acceleration = 4.44 rad/s²
Using the formula:
Making t the subject of the formula:
where;
∴
t = 0.345 s
b)
Using the formula:
here;
= angular displacement
∴
Recall that:
2π rad = 1 revolution
Then;
0.264 rad = (x) revolution
x = 0.042 revolutions
c)
Here; force = 270 N
radius = 1.20 m
The torque = F * r
However;
From the moment of inertia;
given that;
I = 84.4 kg.m²
For re-tardation;
Using the equation
t = 0.398s
The required time it takes= 0.398s