Calculate the initial speed of a box which slides on a horizontal floor surface and comes to rest after sliding 2 s. The coeffic
1 answer:
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Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
v = 2 m/s
Hence, their speed after collision is 2 m/s.
Answer:
Pressure applied by the man= 285103.125 or 41.35
Explanation:
Pressure is defined as the perpendicular force applied per unit area.
i.e.
Now,
where, = mass of the body(man) = 93 kg
= acceleration due to gravity of Earth = 9.81
covered is equal to the area of both stilts(a man generally stands on two feet)
therefore
and putting in the values, we get,
Now we need to convert to our required units:
(We can get the above result by individually converting kg to lb and meters to inches respectively)
Using the above relations we get,