Question

Calculate the initial speed of a box which slides on a horizontal floor surface and comes to rest after sliding 2 s. The coefficient of kinetic friction between the box and the surface is 0.25. (g=9.8 ms-2).

Answer 1

A box sliding on a horizontal floor surface starts out moving at 4.9 m/s and stops after 2 seconds. The surface and the box have a kinetic friction has friction coefficient of 0.25 (g=9.8 ms-2).

The speed of an object at the start of a measurement, or an initial state, is known as the initial speed. The ratio of distance travelled to travel time, also known as the average speed, is the sum of the initial and final speeds. The difference between initial and ending speeds is the speed change. A force that acts between moving surfaces is referred to as kinetic friction. A force acting in opposition to the direction of a moving body on the surface is felt.

Interval (t) equals 2 seconds

Kinetic friction coefficient is 0.25.

gravity-induced acceleration (g) = 9.8 m/s2.

Coming to a stop at a final velocity  of 0 m/s.

Regular force  equals mg

Kinetic friction force is given by  = k.

N = μkmg

I = (delta P) (delta P)

Vo = (0.25)(9.8)(2) (2)

Vo = 4.9m/s

Learn more about kinetic friction here

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