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hjlf
3 years ago
13

A.B,and C are collinear. AB=5x-19,and BC= 3x+4. Find an expression for AC if B is between A and C.

Mathematics
1 answer:
uysha [10]3 years ago
4 0
Find A <span>if B is between A and C.
</span><span>A.B,and C are collinear so A, B and C are line up in a line</span>

AC = AB + BC

AB=5x-19,and BC= 3x+4 given;

So

AC = 5x-19 + 3x+4

Simplify

AC = 8x -15

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Verify the identitiy:
Advocard [28]

Answer:

\frac{sinx}{1-cos x}     =         cosecx  +  cot x

Step-by-step explanation:

To verify the identity:

sinx/1-cosx = cscx + cotx

we will follow the steps below;

We will take just the left-hand side and work it out to see if it is equal to the right-hand side

sinx/1-cosx

Multiply the numerator and denominator by 1 + cosx

That is;

\frac{sinx}{1-cos x}     =    \frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}

open the parenthesis on the right-hand side of the equation at the numerator and the denominator

sinx(1+cosx) = sinx + sinx cosx

(1-cosx)(1+cosx) = 1 - cos²x

Hence

\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}     =  \frac{sinx + sinx cosx}{1-cos^{2}x }

But 1- cos²x  = sin²x

Hence we will replace  1- cos²x  by  sin²x

   \frac{sinx}{1-cos x}    =       \frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}     =  \frac{sinx + sinx cosx}{1-cos^{2}x }   =  \frac{sinx+sinxcosx}{sin^{2}x }

                             

                                  =\frac{sinx}{sin^{2}x }   +   \frac{sinxcosx}{sin^{2}x }

                                   

                                   =\frac{1}{sinx}   +   \frac{cosx}{sinx}

             

                                   =cosecx  +  cot x

\frac{sinx}{1-cos x}     =         cosecx  +  cot x

Note that;

\frac{1}{sinx}  = cosecx                        

         

 \frac{cosx}{sinx}   =       cot x

                                     

6 0
3 years ago
If 2^21 = x + 2^20, what is the value of x ?
andrew-mc [135]

Answer:

x = 1048576

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which shows a graph of a linear equation in standard form Ax + By = C, where A = 0, B is positive, and C is negative? A coordina
IrinaK [193]

Answer:

A coordinate plane with a horizontal line passing through (negative 4, negative 3), (0, negative 3) and (4, negative 3).

Step-by-step explanation:

Ax + By = C, where A = 0, B is positive, and C is negative

By= C or y= C/B which is negative

Since A is zero and C is negative, the line is parallel to x- axis and has negative value for y, so it is a horizontal line below zero

---------------

A coordinate plane with a vertical line passing through (1, negative 4), (1, 0) and (1, 4).

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A coordinate plane with a vertical line passing through (negative 2, negative 4), (negative 2, 0) and (negative 2, 4).

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A coordinate plane with a horizontal line passing through (negative 4, 4), (0, 4) and (negative 4, 4).

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A coordinate plane with a horizontal line passing through (negative 4, negative 3), (0, negative 3) and (4, negative 3).

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8 0
3 years ago
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What is the length x of the right triangle, rounded to the nearest<br> tenth?
Zarrin [17]

Answer:

109.5; B

Step-by-step explanation:

From your identity,

CosA = adjacent/ hypothenus

A represent an arbitrary angle between the sides in question.

In the question above, A=64

Hypothenus is the longest side and adjacent is the side just below the angle .

In the above case,

Hypothenus= X

adjacent =48

This means;

Cos64 = 48 /X

X = 48 / cos64; [ from cross multiplication and diving through by cos64]

X = 48 /0.4383 [ cos64 in radian = 0.4383]

= 109.51

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Note( do your calculation of angle in radian or else, you won't get the answer)

6 0
2 years ago
Please help ASAP, giving lots of points.
BARSIC [14]
The answers is the last one

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