Answer:
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Step-by-step explanation:
This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Compare the enumerators because they have the same denominator. 2 is large than 1 so 2/3 is larger than 1/3
Hope this helps!
Answer: ok we will help
Step-by-step explanation:
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Answer:
9760
Step-by-step explanation:
Interest=((P.A.)*(Interest Rate)*(Time))/100
Interest=(4000*122*2)/100
Interest=9760
