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Savatey [412]
3 years ago
8

Binomial expansion of (x+2)^4

Mathematics
1 answer:
N76 [4]3 years ago
4 0
The two terms are x and 2, thus, x+2 is a binomial.  We have to multiply the binomial by itself four times since it is raised to 4th power.

Let us multiply x+2 by itself using Polynomial Multiplication:

(x+2)(x+2) = x^2 + 4x + 4

Taking the result, let us multiply it again by a+b:

(x^2 + 4x + 4)(x+2) = x^3 + 6x^2 + 12x + 8

And again:

(x^3 + 6x^2 + 12x + 8)(x+2) = x^4 + 8x^3 + 24x^2 + 32x +16

The binomial expansion of (x+2)^4 is  x^4 + 8x^3 + 24x^2 + 32x +16
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The numbers that can divide 648 evenly, using the divisibility tests, include <u>1, 2, 3, 4, 6, 8, 9, 12, and 18</u> and some multiples of any two numbers.

<h3>What is the divisibility test?</h3>

A divisibility test is performed to identify whether a number can be divided evenly by a fixed divisor without a remainder and without actually performing the division process.

<u>Divisibility by 1</u>: Every number is divisible by 1 = 648 (648/1).

<u>Divisibility by 2</u>: 648 is an even number and divisible by 2 = 324.

<u>Divisibility by 3</u>: Sum the digits (18). 18 is divisible by 3 = 6 (18/3).

<u>Divisibility by 4</u>: The last two digits (4 and 8) form a number (12) that is divisible by 4

<u>Divisibility by 6</u>:  It is divisible by 2 and by 3

<u>Divisibility by 8</u>: If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.

<u>Divisibility by 9</u>: Sum the digits (18). 18 is divisible by 9

<u>Divisibility by 12</u>: 648 is divisible by 3 and by 4.

<u>Divisibility by 18</u>: 648 is divisible by 2 and by 9.

Learn more about the divisibility tests at brainly.com/question/24125354

#SPJ1

5 0
2 years ago
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