Answer: 0.42 mg
Step-by-step explanation:
Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.
Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = 
Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-
Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg
Answer:
The range of this function is {-13, -1, 15}.
Step-by-step explanation:
Evaluate f(x) = 4x - 1 at {-3, 0, 4}:
f(-3) = -13
f(0) = -1
f(4) = 15
The range of this function is {-13, -1, 15}.
Answer:
Step-by-step explanation:
Uk
Point P is certainly the outlier because the other points are all consistent with the string of data while Point P is alone with no other data around it.
Answer:
There is some inforrmation that is missing in this question. It should read:
A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .
Answers
Part 1. 0.02
Part 2. 0.0375
Explanation
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)
Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 × 2/10
= 1/10 ×1/5
= 1/50
= 0.02
Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective.
P(3 are defective) = 3/40 × 5/10
= 15/400
= 3/80
= 0.0375
Step-by-step explanation:
