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oksano4ka [1.4K]
3 years ago
14

Three vertices of a rectangle are (–1, 0), (6, 0), and (6, 3).

Mathematics
1 answer:
Orlov [11]3 years ago
6 0
The answer is A. (-1, 3) 

Shown in the picture.

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Complete the solution of the equation. find the value of y when equals -7 <br><br> -3x+6y=-21
vlada-n [284]
If x = -7 then
<span>-3x+6y=-21
</span><span>-3(-7) +6y = -21
21 + 6y = -21
6y = -42
y = -7</span>
8 0
3 years ago
There are black, blue, and white marbles in a bag. The probability of choosing a black marble is 0.36. The probability of choosi
Gala2k [10]

Answer: c) 0.75

Step-by-step explanation:

Given : The probability of choosing a black marble is P(Black)= 0.36.

The probability of choosing a black and then a white marble is P( Black and white) = 0.27.

Then by conditional probability ,

The probability of the second marble being white if the first marble chosen is black = P(\text{white }|\text{Black})=\dfrac{\text{P( Black and white)}}{\text{P(Black}}

=\dfrac{0.27}{0.36}=\dfrac{27}{36}=0.75

Therefore , the probability of the second marble being white if the first marble chosen is black = 0.75

8 0
3 years ago
What are the zeros of the function below? F(x)= (x-1)(x+1)/6(x-4)(x+7)
Lisa [10]

Answer:

+1 and -1

Step-by-step explanation:

The function in this problem is:

f(x)=\frac{(x-1)(x+1)}{6(x-4)(x+7)}

First of all, we have to define the domain of the function, which is the set of values of x for which the function is defined.

In order to find the domain, we have to require that the denominator is different from zero, so

6(x-4)(x+7)\neq 0

which means:

x\neq 4\\x\neq -7

So the domain is all values of x, except from 4 and -7.

Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:

(x-1)(x+1)=0

This is verified if either one of the two factors is equal to zero, therefore:

x-1=0\\\rightarrow x=+1

and

x+1 = 0\\\rightarrow x=-1

We see that both values are part of the domain, so they are acceptable values: so the zeros of the function are +1 and -1.

7 0
3 years ago
Please answer question in picture below
Sonja [21]
9×7=63
63÷2=31.5
31.5×4=126

7×7=49

126+49=175

175 is the answer
8 0
3 years ago
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 101010 denarii per day to support 444
givi [52]

<u>the correct question is</u>

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?

Let

x-------> the cost to support a legionary per day

y-------> the cost to support an archer per day

we know that

4x+4y=10 ---------> equation 1

2x+2y=5 ---------> equation 2

If you multiply equation 1 by 2

2*(2x+2y)=2*5-----------> 4x+4y=10

so

equation 1 and equation 2 are the same

The system has infinite solutions-------> Is a consistent dependent system

therefore

<u>the answer is</u>

We cannot solve for a unique cost for each soldier, because there are infinite solutions.

5 0
3 years ago
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