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Bogdan [553]
3 years ago
11

Smallest to largest?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer:

B. <Q, <P, <R

Step-by-step explanation:

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An isosceles right-angled triangle is shown.
Bad White [126]

Answer:

\boxed{x=4}

Step-by-step explanation:

Area of triangle = 0.5 × Base × Height

→ Substitute in the values

200 = 0.5 × 5x × 5x

→ Simplify

200 = 12.5x²

→ Divide both sides by 12.5

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6 0
3 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
zach deposits $15,000 into his savings account. his savings account has an annual interest rate of 1.4%. how much money in inter
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Do $15,000x.014x2
--
$15,000x.014=$210
$210x2=$420
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If x + 3 = 10, then x = 7.<br><br><br> Statement<br><br><br> Reasons
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