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victus00 [196]
4 years ago
15

Write a recursive formula for the sequence

Mathematics
1 answer:
Over [174]4 years ago
3 0

Answer:

The answer is:O f(1) = 10, f(n) = f(n − 1) + 2, for n > 1

Step-by-step explanation:

f1=10 because the first number is 10. then f(n)=f(n-1)+2 for N because it goes up 2 every time.

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Ok can some really help me on this.
Mkey [24]

Answer:

give more information and i will give the right answer

Step-by-step explanation:

6 0
3 years ago
Please help me!!! Brainliest
Luba_88 [7]
The lines are parallel.

In order to figure this out, let's start off by simplifying both equations as much as we can:
2y = 16 + 4x
Divide by 2
y = 2x + 8

Remember that the slope of that equation is '2' since 'm' in the equation y = mx + b represents slope.

Simplify the next equation:
6y - 30 = 12 x
6y = 12x + 30
Divide by 6:
y = 2x + 5

As you can tell, this line also has a slope of 2.
Parallel lines is defined as two lines that have the same slope. Knowing this, we can infer that these two lines are parallel.

-T.B.
7 0
3 years ago
If C(m) = 0.50m + 30 represents the cost of renting a car, how many miles were driven if the cost is $130?
Dimas [21]
Your answer is 200 miles
3 0
3 years ago
The quotient of two numbers is negative what must be true about the two number
ahrayia [7]

Answer:

when you divide a negative number by a negative number the quotient is always positive.when you divide two negative number then the quotient is always positive

Step-by-step explanation:

:>

7 0
4 years ago
I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

(-6n^{-3})^2

We can use the power of a product property, where:

(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}

6)

We have the expression:

-\frac{3x^0}{x^4}

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

=-\frac{3}{x^4}

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

x^n=\frac{1}{x^{-n}}

And vice versa:

\frac{1}{x^{-n}}=x^n

So, we can write the above as:

=-\frac{3}{x^4}\\=-\frac{3}{x^{-(-4)}}\\=-3x^{-4}

However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
4 years ago
Read 2 more answers
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