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slava [35]
1 year ago
14

number 3 says,"If u and v are the measures of complementary angles such that sin u =2/5 and tan v =(square root of 21) 21/2, lab

el the sides and angles of the right triangle in the diagram below with possible side lengths.

Mathematics
1 answer:
vodomira [7]1 year ago
5 0

Answer and Explanation:

Using trig ratios, we can express the given values of sin u and tan v as shown below

\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}

So we can go ahead and label the sides of the triangle as shown below;

We can find the value of u as shown below;

\begin{gathered} \sin u=\frac{2}{5} \\ u=\sin ^{-1}(\frac{2}{5}) \\ u=23.6^{\circ} \end{gathered}

We can find v as shown below;

\begin{gathered} u+v+90=180\text{   (sum of angles in a triangle)} \\ v+23.6+90=180 \\ v=180-113.6 \\ v=66.4^{\circ} \end{gathered}

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HELP PLEASE <br><br>must show work ​
matrenka [14]

Answer:

1. 4n^3

2. 4k^7

3. 3

4. -30x

5. -6

Step-by-step explanation:

1. The prime factorization of 12 is 2 x 2 x 3 and the prime factorization of 16 is 2 x 2 x 2 x 2. When you look at these two expressions you can see the common factors of these two numbers are 2 x 2, which is 4. Next, we look at the GCF of the N's which would be n^3 since n^5 has three N's in it. Therefore, we get 4n^3 when we multiply the two together.

2. The factors of 8 are 1, 2, 4, and 8. Out of these, 1, 2, and 4 are the only factors that 20 shares with it and 4 is the greatest. Then, we look at the K's and the GCF of the K's is k^7 since k^8 has seven K's. We multiply the two and we get 4k^7.

3. Since one of the numbers of the three given here does not include the variable n, there will not be any N's in the GCF of the three, so we don't have to worry about that. Now, we just find the GCF of 18, -24, and -21. The factors of 18 are 1, 2, 3, 6, 9, and 18, the factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24, and lastly, the factors of 21 are 1, 3, 7, and 21. From these, 3 is the biggest common divisor, therefore the GCF is 3.

4. Between the two X's, X^1 is the biggest amount of X's this GCF has, so the final GCF will be some constant multiplies with X. Since we are dealing with bigger numbers on this problem, we should use prime factorization. The prime factorization of 90 is 2 x 3 x 3 x 5, and the prime factorization of 120 is 2 x 2 x 2 x 3 x 5. From these expressions, we take the biggest amount of each common factor as we can. Since these expressions both have 2, we take the smaller amount of 2's which is one two. Then we get one three from both expressions, and one five as well. 2 times 3 times 5 equals 30, therefore, we get -30x, and not 30x, because both of these numbers are negatives.

5. All of these numbers do not have an x, so there won't be an x in our GCF. Another method of quickly finding the GCF of numbers is to look at the smallest number's factors first to see what factors it shares with the other numbers. The factors of 12 are 1, 2, 3, 4, 6, and 12. 42 and 30 do not have the factor 12, so we can go down the list and see if 42 and 30 share the factor 6, which they do since 6 times 7 is 42 and 6 times 5 is 30. Since all of these numbers share the negative sign, the GCF of these three numbers is -6.  

5 0
3 years ago
An unconditional acceptance into a graduate program at a university will be given to students whose GMAT score plus 100 times th
Talja [164]

Answer:

​Robbin's grade point average must be at least 2.75 in order to be unconditionally accepted into the program. ​

Step-by-step explanation:

An unconditional acceptance into a graduate program at a university will be given to students whose GMAT score plus 100 times the undergraduate grade point average is at least 1075

Considering the GMAT score x, and the GPA y, this situation is modeled by the following inequality:

x + 100y \geq 1075

Robbin's GMAT score was 800.

This means that x = 800, and thus:

x + 100y \geq 1075

800 + 100y \geq 1075

100y \geq 275

What must her grade point average be in order to be unconditionally accepted into the​ program?

Solving the above inequality for y:

100y \geq 275

y \geq \frac{275}{100}

y \geq 2.75

Thus:

​Robbin's grade point average must be at least 2.75 in order to be unconditionally accepted into the program. ​

7 0
3 years ago
What is, 7 3/10+6 1/3+2 7/10?
snow_lady [41]

7 3/10 + 6 1/3 + 2 7/10

First change them to improper fractions

73/10 + 19/3 + 27/10

now find the common denominator which would be 30

73/10 = 219 /30

19/3 =   190/30

27/10 =  81 /30

now add (219 + 190 + 81) = 490/30

now divide 490 ÷ 30 = 16 1/3

Your answer is 16 1/3

Hope this helps. :)

6 0
3 years ago
Read 2 more answers
3 more than 6 times a number
Snowcat [4.5K]

Answer:

assuming you're looking for an expression, it would be written as "6x+3".

4 0
3 years ago
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Fred runs 4 laps around a track in 6 minutes. How many minutes per lap is that? How many laps per minute?
denis-greek [22]

Answer:

0.67 Laps per minute

Step-by-step explanation:

4 Laps over 6 Minutes

4/6 = 0.67

8 0
3 years ago
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