All categories

2 years ago

Find two consecutive integers whose sum is 373.

Mathematics

1 answer:

nadya68 [22]2 years ago

4 0

Answer:

186 and 187

Step-by-step explanation:

Let n be the first integer.

Then n+1 is the next integer.

We are given their sum is 373.

n+(n+1)=373

Combine like terms:

2n+1=373

Subtract 1 on both sides:

2n=372

Divide both sides by 2:

n=186

So n+1=187.

187

+186

--------

373

You might be interested in

While waiting for a video game to download you notice that 30% of 32,000 kilobytes have been dowloaded so far

Ghella [55]

30% of 32000 will be 32000 multiplied by 0.3 which would equal 9600 kilobytes

7 0

3 years ago

Read 2 more answers

First answer I will give you brainleyist

asambeis [7]

Answer: C 6 cm
Sorry if I’m wrong

8 0

2 years ago

Show work to above problem

Len [333]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
|a|\implies 
\begin{cases}
+a\\
-a
\end{cases}\implies \pm a\\\\
-------------------------------\\\\
(16x^2)^{\frac{1}{2}}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm\sqrt{4^2x^2}\implies \pm\sqrt{(4x)^2}\implies \pm 4x
\\\\\\
\begin{cases}
+4\\
-4
\end{cases}\implies |4x|$

5 0

3 years ago

R / 5 - 6 equal negative 1

Fofino [41]

Answer:

R = 25

Step-by-step explanation:

Given

$\frac{R}{5}$ - 6 = - 1

Multiply through by 5 to clear the fraction

R - 30 = - 5 ( add 30 to both sides )

R = 25

4 0

3 years ago

What is the other solution??

Vladimir79 [104]

Answer:

The other solution is 12.

Step-by-step explanation:

Break the solution into groups: (x^2+2x)+(-12x-24)

Factor out the x^2 from the first group to get x(x+2)

Factor out the -12 out of the second group to get -12(x-12)

Here we get (x-12)(x+2)

You can see solutions are -2 and 12.

4 0

2 years ago

Read 2 more answers