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3 years ago

What's the difference in terminating or repeating a decimal

1 answer:

7 0

A repeating decimal is when the number repeat or go on forever and do not change
a terminating decimal is one that has an end to it's numbers

example of repeating: .303030303030303.....
example of terminating: .2427

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Will mark brainliest!!

enyata [817]

Answer:well you see this is easy first you look at the 113 divide that by 4 multiply by 2 and then square root and you have your answer which would be d <4

Step-by-step explanation:

3 0

3 years ago

Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 h, (, x, ), equals, start fraction, 1, divided

tiny-mole [99]

Answer:

$\dfrac{47}{60}$ sq. units.

Step-by-step explanation:

The given function is

$h(x)=\dfrac{1}{7-x}$

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

$Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)$

For given question,

$Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)$

$Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)$

$Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)$

Now,

$Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)$

$Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}$

$Area=\dfrac{12+15+20}{60}$

$Area=\dfrac{47}{60}$

Therefore, the required area is $\dfrac{47}{60}$ sq. units.

5 0

3 years ago

Multiply these polynomials.

maksim [4K]

When we multiply the polynomials we will get:
(5x^2+2x)(3x^2-7x+4)
=5x^2(3x^2-7x+4)+2x(3x^2-7x+4)
=15x^4-35x^3+20x^2+6x^3-14x^2+8x
=15x^4+(6x^3-35x^3)+(20x^2-14x^2)+8x
=15x^4-29x^3+6x^2+8x
The correct answer is C

4 0

3 years ago

A randomly generated list of integers from 1 to 5 is being used to simulate an

elena55 [62]

Answer: it’s 40% if your confused… aka (A.)

Step-by-step explanation:

4 0

3 years ago

Describe how to determine the average rate of change between x = 3 and x = 5 for the function f(x) = 3x3 + 2. Include the averag

Serhud [2]

Answer:

147

Step-by-step explanation:

Average rate of change is given by the total rise over total run.

$f(x) = 3x^3+2\\f(3)=3*3^3+2=83\\f(5)=3*5^3+2 = 377$

So,

total rise = 377 - 83 = 294

total run = 2

average rate of change = $\dfrac{294}{2} = 147$

8 0

3 years ago