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Usimov [2.4K]
3 years ago
11

The decimal 104.3 became 1,043 when multiplied by 10. The same number becomes 10.43 when multiplied by 0.10. Explain why

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0
Because dividing by 0.10 is the same as dividing by 10
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( m + 4 ) ( m + 1 )
love history [14]
(m+4)(m+1)

=m^2+5m+4........
3 0
3 years ago
Solve the equation.<br> 9x=25
lidiya [134]

Answer:

x = \frac{25}{9}

Step-by-step explanation:

Divide both sides by 9 to isolate x:

\frac{9x}{9} = \frac{25}{9}  \\x = \frac{25}{9}\\

Hope this helps!

8 0
3 years ago
Is 14 200 000 in scientific notation 1.42 10x,5
Elan Coil [88]

Yes, the rules of scientific notation are:

1. All non-zero digits are significant

2. Zeros in between non-zeros are significant.

3. Zeros to the left of the first non-zero number are NOT significant.

4. Zeros to the right of non-zero numbers are significant IF a decimal point is present.

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6 0
3 years ago
Solve for k 5/8(3k+1)-1/4(7k+2)=1
lesya [120]

Answer:

<h2>k = 7</h2>

Step-by-step explanation:

\dfrac{5}{8}(3k+1)-\dfrac{1}{4}(7k+2)=1\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{5}{8\!\!\!\!\diagup_1}(3k+1)-8\!\!\!\!\diagup^2\cdot\dfrac{1}{4\!\!\!\!\diagup_1}(7k+2)=8\cdot1\\\\5(3k+1)-2(7k+2)=8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(5)(3k)+(5)(1)+(-2)(7k)+(-2)(2)=8\\\\15k+5-14k-4=8\qquad\text{combine like terms}\\\\(15k-14k)+(5-4)=8\\\\k+1=8\qquad\text{subtract 1 from both sides}\\\\k=7

3 0
3 years ago
In how many ways can six people sit in a six-passenger car?
nekit [7.7K]

Answer:

number of ways = 720

Step-by-step explanation:

The number of ways  six people sit in a six-passenger car is given by the number of permutations of 6 elements in 6 different positions ( seats), then

number of ways = number of permutations of 6 elements = 6! = 6 * 5 * 4 *3 * 2 * 1 = 720

Since the first person that sits can be on any of the seats , but then the second person that sits can choose any of 5 seats (since the first person had already occupied one) , the third can choose 4 ... and so on.

5 0
4 years ago
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