How do you solve this?
1 answer:
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Because ABCD is a rhombus, ΔABC ~ ΔADC.
The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12
Therefore the area of ABCD = 2*12 = 24
Answer: 24
The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12
Therefore the area of ABCD = 2*12 = 24
Answer: 24