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padilas [110]
3 years ago
7

Which is​ greater, the amount the average person spends in a month on coffee or the amount the average person spends in a month

on​ gasoline?
Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

The correct answer is the amount the average person spends in a month on gasoline.

Step-by-step explanation:

When comparing the amounts spent on the purchase of two items, we must need to see the price difference between the products first, then we will see the consumption of those products. Here the two items that are being compared have different purchase prices. A cup of Coffee is far cheaper than purchasing a tank of gasoline. If coffee is purchased on daily basis, even then the amount spent on purchasing coffee would be much lesser than the amount spent on buying the gasoline. For example, the cup of coffee costs $1 and a tank of gasoline costs $50. If coffee is purchased daily, then monthly amount spent on it will be $30, and if gasoline is purchased twice in a month, the amount spent on it will be $100. So an average person spends more amount on gasoline than on purchasing coffee.

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Answer:

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Step-by-step explanation:

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Dividing both equations:

\frac{sin(\phi) sin(\theta)}{sin(\phi)cos(\theta)} = tan(\theta) = 0.2/(-0.3)=-2/3\\

Therefore:

arctan(θ) = -2/3

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Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given expression is

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\rm :\longmapsto\:\dfrac{1}{ \sqrt{3}   -   \sqrt{2}   +  \sqrt{5} }

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On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{1}{( \sqrt{3}  -  \sqrt{2} ) +  \sqrt{5} }  \times \dfrac{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }

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\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}

So, using this, we get

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\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} } =\dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}}}

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<h3><u>More Identities to </u><u>know:</u></h3>

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\purple{\boxed{\tt{  {(x - y)}^{3} =  {x}^{3} - 3xy(x  -  y) -  {y}^{3}}}}

\pink{\boxed{\tt{  {(x + y)}^{2} +  {(x - y)}^{2} = 2( {x}^{2} +  {y}^{2})}}}

\pink{\boxed{\tt{  {(x + y)}^{2}  -  {(x - y)}^{2} = 4xy}}}

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