3 years ago

The value of x-y is negative, and x and y are both positive. What can you conclude about the values of x

1 answer:

3 0

Well for two positive numbers subtracted to equal a negative number, the first number must have a value that is less than the second number. (Ex. 3-4= -1) In this case, you can conclude that x is less than y! (x<y)

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Please see attached image and help with these absolute value problems - thank you

Novay_Z [31]

Answer:

{-infinity, infinity}

no solution

Step-by-step explanation:

|x| +15≥4

Subtract 15 from each side

|x| +15-15≥4-15

|x| ≥-11

This is always true so x can be and real number

{-infinity, infinity}

-2|5x+3| = 8

Divide by -2

-2/-2|5x+3| = 8/-2

|5x+3| = -4

This can never happen because absolute values are zero or greater

no solution

6 0

3 years ago

Which values of m and b will create a system of equations with no solution? Select two options. y = mx + b y = –2x + A system of

Nuetrik [128]

Answer:

m = -2 and b = -1/3

m = -2 and b = -2/3.

Step-by-step explanation:

y = -2x - 1/3

y = -2x - 2/3

This system has no solutions because y cannot be 2 different values at once.

5 0

3 years ago

Read 2 more answers

2 questions in one.<br> Help?..

daser333 [38]

Answer:

2. 3

3. 4^45

Step-by-step explanation:

${ ({5}^{4} ) }^{m} = {5}^{12} \\ = > {5}^{4m} = {5}^{12} \\ = > 4m = 12 \\ = > m = \frac{12}{4} \\ = > m = 3 \\ \\ number \: of \: books \: at \: library \\ = {({4}^{9})}^{5} \times {4}^{0} \\ = {4}^{45} \times 1 \\ = {4}^{45}$