Can someone please answer this for me?!

Mathematics

1 answer:

Nutka1998 [239]3 years ago

8 0

$3x - 3y = 9 \\ - 3x \: \: \: \: \: \: \: - 3x \\ - 3y = - 3x + 9 \\ \div - 3 \: \div - 3 \div - 3 \\ y = - x - 3$
From here work should be easy. (0,-3)(3,-6)(8,-11) just put in the y's as the answer because that's what they ask

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Check all that apply. if secØ= 13/12, then:

makvit [3.9K]

Based on trigonometric formulas, we can find that the options that applies to the given trigonometric relationship are tan θ = 5/12 and cos θ = 12/13.

<h3>How to find the exact form of trigonometric functions</h3>

There six trigonometric functions, which are related by a group of expressions, which will be used in this question:

$\cos \theta = \frac{1}{\sec \theta} = \frac{12}{13}$

$\sin \theta = \sqrt{1 - \cos^{2}\theta}$

$\sin \theta = \sqrt{1 -\left(\frac{12}{13} \right)^{2}}$

$\sin \theta = \frac{5}{13}$

$\csc \theta = \frac{1}{\sin \theta} = \frac{13}{5}$

$\tan \theta = \sqrt{\sec^{2}\theta - 1}$

$\tan \theta = \sqrt{\left(\frac{13}{12} \right)^{2}-1}$

$\tan \theta = \frac{5}{12}$

Based on trigonometric formulas, we can find that the options that applies to the given trigonometric relationship are tan θ = 5/12 and cos θ = 12/13.

<h3>Remark</h3>

The statement is incomplete. Complete form is shown below:

Check all that apply:

If sec θ = 13/12, then:

a) sin θ = 12/13

b) tan θ = 5/12

c) cos θ = 12/13

d) csc θ = 12/13

To learn more on trigonometric equations: brainly.com/question/22624805

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5 0

2 years ago