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Rashid [163]
3 years ago
12

Explain, in complete sentences, which method you would use to solve the following system of equations and why you chose that met

hod. Show your work and provide the solution to the system.
4x + 3y = 2
3x + 2y = 1
Mathematics
1 answer:
svp [43]3 years ago
4 0
I would use elimination. I would multiply 4x+3y=2 by 3 so the it becomes 12x+9y=6, and I would multiply the bottom equation by 4 so that it becomes 12x+8y=4. Because I am using elimination I have to get rid of one variable, I chose to get rid of X hence that the coefficient of X in each equation is now 12. i simply subtract both equations and get y by itself. y=2. I plug in Y to find x in either of the original equations, where I get x=-1. To check my work substitute the values of x and y in the other equation. 4(-1)+3(2)=2 ------->  2=2
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What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16
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Answer:

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Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

y\left(y+4\right)-4\left(y-4\right)=9

y^2+4y-4y+16=9

y^2=9-16

y^2=-7

take squar root of both sides

y=\pm \sqrt{-7}

y=\pm i \sqrt{7}

Hence final answer is y=\pm i \sqrt{7}.

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