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3 years ago

Equivalent fraction for 12/15

Mathematics

2 answers:

WINSTONCH [101]3 years ago

7 0

24/30
48/60
96/120
Those Are Three Equivalent Fractions For 12/15 --> 80%

alexira [117]3 years ago

4 0

Here are some of the equivalent fractions for 12/15 4/5, 8/10, 12/15, 16/20, 20/25, 24/30, 28/35, 32/40, 36/45, 40/50,

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What are the answers to all of these questions?

VikaD [51]

We have that

N 11)
a) graph the equation y=x²-3x-10

using a graph tool
see the attached figure

b) Determine the roots of the equations
the roots of the equations are the values for y=0
x²-3x-10=0
x²-3x-10=(x+2)*(x-5)=0
the roots are
x1=-2
x2=5

see the attached figure problem 11

N 12) what is the value of x in the equation?
3x²=7x

3x²=7x-------> 3x²-7x=0--------> x*(3x-7)=0

x1=0
3x-7=0------> 3x=7------> x=7/3

the values of x are
x1=0
x2=7/3---> 2.33
see the attached figure problem 12

N 13) what is the value of x in the equation?
x²-5x=6----------> x²-5x-6=0
x²-5x-6=0-------> (x+1)*(x-6)=0
the values of x are
x1=-1
x2=6

N 14) what is the value of x in the equation?
2x²-5x=12--------> 2x²-5x-12=0

using a graph tool
see the attached figure problem N 14
2x²-5x-12=0----------> (x+3/2)*(x-4)=0

the values of x are
x1=-3/2
x2=4

7 0

3 years ago

What is a pattern rule for 2,7,12,17... .

Mamont248 [21]

Answer:

Step-by-step explanation:

you add five to each number to get the next

7 0

3 years ago

Read 2 more answers

15 + 13d + 12 helpppp

VladimirAG [237]

Answer:

its 13d+27

Step-by-step explanation:

8 0

3 years ago

7. A recent medical survey reported that 45% of the respondents felt that the doctor explained their condition in a sufficient m

vovikov84 [41]

Answer:

a)0.866

b)0.9623

Step-by-step explanation:

8 0

3 years ago

The closed form sum of

zalisa [80]

Perhaps you know that

$S_2 = \displaystyle\sum_{k=1}^n k^2 = \frac{n(n+1)(2n+1)}6$

and

$S_3 = \displaystyle\sum_{k=1}^n k^3 = \frac{n^2(n+1)^2}4$

Then the problem is trivial, since

$\displaystyle\sum_{k=1}^n k^2(k+1) = S_2 + S_3 \\\\ = \frac{2n(n+1)(2n+1)+3n^2(n+1)^2}{12} \\\\ = \frac{n(n+1)\big((2(2n+1)+3n(n+1)\big)}{12} \\\\ = \frac{n(n+1)\big(4n+2+3n^2+3n\big)}{12} \\\\ = \frac{n(n+1)(3n^2+7n+2)}{12} \\\\ = \frac{n(n+1)(3n+1)(n+2)}{12}$

Then

$12\bigg(1^2\cdot2+2^2\cdot3+3^2\cdot4+\cdots+n^2(n+1)\bigg) = n(n+1)(n+2)(3n+1)$

so that a = 3 and b = 1.

4 0

3 years ago