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elena-s [515]
3 years ago
8

What is the greatest common factor (GCF) of the numerator and denominator

Mathematics
2 answers:
lesya [120]3 years ago
6 0

Answer: x+5

Step-by-step explanation:

A

P

E

X

ad-work [718]3 years ago
4 0

Answer:

C

Step-by-step explanation:

x²+2x-15 = x²-3x+5x-15 = x(x-3)+5(x-3)=(x+5)(x-3)

or delta:

∆=2²-4*1*(-15)=4+60=64

√∆=8

x1 = (-2+8)/2 = 3

x2=(-2-8)/2=-5

and 4x+20 = 4(x+5)

The same is (x+5), so it is GCF. answer C

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How do I answer 2 (x + 2) = -4?
maw [93]
Divide both sides by 2 2(x+2)=-
move constant to the right x+2=-2
calculate x=-2-2
x=-4

5 0
3 years ago
Require full steps working for this question
Ray Of Light [21]

I let the computer do the graphing.  

f(x) = x(x + 3)²(1 - x) / 3

We see obvious zeros at x=0, x=-3 and x=1.

f(x) = x(x + 3)²(1 - x) / 3

f(x) = x(x^2 + 6x + 9)(1 - x)/3

f(x) = x(x^2 + 6x + 9 - x^3 - 6x^2 - 9x)/3

f(x) = x(- x^3 - 5x^2 -3x +9)/3

f(x) = (-x^4 - 5x^3 -3x^2 +9x)/3

f'(x) = (-4x^3 - 15x^2 -6x + 9)/3

We know there's f'(-3)=0 so x+3 must be a factor here,

f'(x) = (x + 3) (-4x^2 - 3x + 3)

We get stationary points when x = -3 or

x = (-1/8)( 3 ± √(9 - 4(-4)(3))) =  (-3 ± √57)/8  about -1.3 and 0.6 which are a local minimum and maximum respectively.

f''(x) = (-12x^2 - 30x -6)/3 = -4x^2 - 10x - 2

f''(-3) = -4(9)+ 30 - 2 = -8

Concave Down, Negative.   (-3,0) is a local maximum.

f''((-3 - √57)/8) = -4(-1.3)^2 - 10(-1.3) - 2 = 4.24

Concave up, positive, a CUP

(-3 - √57)/8, f((-3 - √57)/8) ) is a minimum.

f''((-3 + √57)/8) = -4(.6)^2 - 10(.6) - 2 = -9.44

CDN, ( ((-3 + √57)/8), f((-3 + √57)/8) ) is a maximum.

I didn't evaluate f((-3 ±√57)/8) which are around -3 and 1 but I leave that calculation to you.

6 0
3 years ago
Multiply 8 times the square root of 3 by 9 times the square root of 27.
Viktor [21]
8√3 · 9√27
8 · 9 ·√3 · √27
72 · √81
72 · 9
648

The answer is 648. :)
6 0
3 years ago
PLEASE HELP ASAP
Aneli [31]

Answer:

its is 192 I just took this assignment

3 0
3 years ago
BRAINLIESSTTTT!!!
Yuri [45]

The answer would be B because the sum of the squares of the 2 shorter sides equal the square of the longer side, which is the pythagoream theorem of a^2+b^2=c^2.

5 0
3 years ago
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