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Nata [24]
3 years ago
9

An object is launched from a platform.

Mathematics
1 answer:
Bess [88]3 years ago
4 0

Answer:

60 feet

Step-by-step explanation:

The height, h (in meters), of the object launched from a platform is represented by the equation

h=h(x)=-5x^2+20x+60

where x is the time (in seconds) passed after the launch.

The time of launch is x=0 (0 seconds passed after the launch)

Substitute x=0 to find the height:

h=h(0)=-5\cdot 0^2+20\cdot 0+60=60\ feet

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Cos (314) = .694 is positive
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3 A random sample of 100 PUJ (public utility jeep) shows that a jeepney is driven on the average 24,500 km per year, with a stan
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Step-by-step explanation:

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2 years ago
Anyone know how to do these?
erastovalidia [21]

Answer:

B. 1/m¹⁸

Step-by-step explanation:

To simplify the equation, we start with the values inside the brackets.

Therefore  m⁻¹m⁵ results to m⁴.

This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.

that is, -1+5=4

then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶

To divide figures that have the same base we subtract the powers.

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the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸

3 0
3 years ago
Read 2 more answers
Identify terms and factors: - 4x + 2x2<br>y​
DedPeter [7]

Answer:

=2x2y−4x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The radius of the base of a cylinder is 10 centimeters and its height is 20 centimeters A cone is used to fill the cylinder with
rewona [7]

Answer:

24 times

Step-by-step explanation:

cone is used to fill cylinder

conevolume times x=cylindervolume

so

x=cylinderv/conev

cylinderv=hpir^2

conevolume=1/3hpir^2

cylinder:

v=hpir^2

r=10

h=20

v=20*pi*10^2=2000π

cone=1/3hπr²

r=5

h=10

v=1/3(10)π5²=250π/3

volume of cylinder ÷ volume of cone

= 2000π ÷ (250π÷3)

= 6000π ÷ 250π

= 600÷25

= 24

please mark me brainliest

6 0
3 years ago
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