<img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%5Csqrt%7B5%20-%202x%7D%20" id="TexFormula1" title=" f(x) = \sqrt{5

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Anvisha [2.4K]

2 years ago

" alt=" f(x) = \sqrt{5 - 2x} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

olganol [36]2 years ago

3 0

Inverse:
$- \frac{x^{2} }{2} + \frac{5}{2}$
I hope this what you asked for?!

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The answer is: -36jk

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3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

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Answer:

Latoya:

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= 11 : 9

Lem : total = 9 : 20

Parker:

cran : lem = 2 1/2 : 3 1/2

= 5/2 : 7/2

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Lem : total = 7 : 12

Step-by-step explanation:

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Irina-Kira [14]

45-9=36/18=2 I hope this helps

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Each of four friends orders a sweatshirt from a catalog. There are 18 colors of sweatshirts, 6 of which are all cotton and 12 of

Digiron [165]

Answer:

1/204.

Step-by-step explanation:

That would be

6/18 * 5/17 * 4/16 * 3/15

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