A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
e given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+248x+116
1 answer:
Answer:
Step-by-step explanation:
The rocket will hit the ground when y = 0. If you use the quadratic equation:
x = (-248±√(2482-4(-16)(116))/(2(-16))
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