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AVprozaik [17]
3 years ago
10

Y+6=-6(x+3) rewrite the equation in Ax+By=C

Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

y=-6x-24

Step-by-step explanation:

just expand

y+6=-6x-18

then move the six from the left to the right

y=-6x-24

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Use Bidmas, solve all the inner brackets (), with first division, then multiplication then addition then subtraction
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3 years ago
Solve x+4=10 A.x=2 B.x=3 C.x=6 D.x=14
labwork [276]

Answer:

C. x = 6

Step-by-step explanation:

6 + 4 = 10

8 0
2 years ago
How Many Solutions?<br> 3x - 7 = 3(x - 3) + 2<br> No Solution<br> One Solution<br> Infinite Solution
prisoha [69]

Answer:

Infinite Solutions

Step-by-step explanation:

3x-7=3x(x-3)+2

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3 0
3 years ago
Use the polynomial 3x^2−4x^11+4x^4−2x^10−5+^8x^8 to answer the question. 
Anit [1.1K]

Answer: 11

<u>Step-by-step explanation:</u>

3x² - 4x¹¹ + 4x⁴ - 2x¹⁰ - 5 + 8x⁸

To find the degree, look for the largest exponent.  <em>11</em>

If you put this polynomial in standard form (from largest to smallest exponent), the first term will give you the degree of the polynomial and the leading coefficient.

- 4x¹¹ - 2x¹⁰ + 8x⁸ + 4x⁴ + 3x² - 5

4 0
3 years ago
Read 2 more answers
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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