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inysia [295]
3 years ago
10

Find the area and perimeter for number 19 and 20 with work please

Mathematics
1 answer:
allsm [11]3 years ago
8 0
I promise if you use the internet it will come up
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A model house has a scale of
Lapatulllka [165]

Answer: Assuming that you mean 1in:2ft the model house would be 13 inches wide.

Step-by-step explanation: well 1 is half of 2 right? So if you want to get the numbers easier to use then just divide that 26 by 2 and then you get the scale 1in:1ft. From there it is easy, 13 feet of the real house= 13 inches in the model house

5 0
1 year ago
Multiplying fraction 5 5/9×2 16/25
Angelina_Jolie [31]
You can convert them to decimals and multiply. Remember when using decimals, it is over 10 or 100 <span />
3 0
3 years ago
Read 2 more answers
Please explain step by step for 0.67÷0.3=?
pentagon [3]
Multiply each of the numbers by a ten to a power that they both become whole numbers.

0.67 * 10^2 = 67
0.3 * 10^2 = 30

Divide as usual.

67 / 30 = 2 \frac{1}{3}

So, the answer is 2 1/3.
3 0
3 years ago
Beth has already jogged 3 miles. She plans to jog less than 12 miles. Which inequality can be used to find the number of miles (
nika2105 [10]

Answer: Bilmem

Step-by-step explanation:

5 0
2 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
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