Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y = ![\frac{1}{2}[3000-3x]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B3000-3x%5D)
y = 1500 - 
Now area of the rectangle A = xy square feet
A = x[
]
For maximum area 
A' =
= 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 - 
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000
1 yr = 12 months
4 yrs= 12x4 = 48 months
3/4 year= 3/4 x12 = 9
so 4 3/4 years= 48+9 =57 months
Answer:
Step-by-step explanation:
Y)
= 3
*multiply both sides by 8 - cancels out 8 in denominator*
x + 4 = 24
*subtract 4 from both sides*
x = 20
E)
= 1
*multiply both sides by 2 - cancels out 2 in denominator*
x - 5 = 2
*add 5 on both sides*
x = 7
N)
= 2
* multiply both sides by 4 - cancels out 4 in denominator*
x + 2 = 8
*subtract 2 from both sides*
x = 6
90 + 8 ? What are you asking? :)
Simplify
10/3
Convert to a mixed fraction
3 1/3