Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
#SPJ1
Answer:
BC = 6.8
Step-by-step explanation:
The distance from A to B, then from B to C, is the same distance as from A to C.
Thus,
AB + BC = AC
AB = 8x + 8
BC = 4x + 2
AC = 22
AB + BC = AC
(8x + 8) + (4x + 2) = 22
Expanding the parenthesis:
8x + 8 + 4x + 2 = 22
8x + 4x + 8 + 2 = 22
12x + 12 = 22
Subtracting 12 from both sides:
12x = 10
Dividing both sides by 12:
x = 10/12 = 1.2
x = 1.2
We're looking for BC. As we know,
BC = 4x + 2
Let's now put in x = 1.2 into this equation:
BC = 4x + 2
BC = 4 * 1.2 + 2
Since 4 * 1.2 is 4.8:
BC = 4.8 + 2
BC = 6.8
Answer: BC = 6.8
Is means =
less than is subtract
1/2a -8=2
if you need to know how to do it let me know
answer- 18
explanation- 40% of 120= 48 and 25% of 120= 30.
hope this helps !
Hi,
The answer you are looking for is x= -3.
Have a great day!!
